Tabili ti akoonu
C6H5NH3Cl | + | NÁOH | → | C6H5NH2 | + | H2O | + | NaCl | |
Aniline hydrochloride; CI76001; Benzenamine hydrochloride | iṣuu soda hydroxide | omi | iṣuu soda kiloraidi | ||||||
(dd) | (ẹsẹ) | (rn) | |||||||
(không máa) | (trắng) | ||||||||
1 | 1 | 1 | 1 | 1 | Hệ số | ||||
Nguyên - Phân tử khối (g / mol) | |||||||||
Sẹ mol | |||||||||
Kối lượng (g) |
Ko si alaye ti o wa fun idogba kemikali yii
Alaye: Awọn ipo ayika ti o dara julọ fun iṣesi, gẹgẹbi iwọn otutu, titẹ, awọn ayase, ati epo. Awọn ayase jẹ awọn oludoti ti o yara iyara (iyara) ti iṣesi kemikali laisi jijẹ tabi di apakan ti ọja ipari. Awọn ayase ko ni ipa lori awọn ipo iwọntunwọnsi.
Fun C6H5NH3Cl
Ninu gbolohun ọrọ ni kikun, o tun le sọ C6H5NH3Cl (Aniline hydrochloride; CI76001; Benzenamine hydrochloride) fesi pẹlu NaOH (sodium hydroxide) ati gbejade C6H5NH2 () ati H2O (omi) ati NaCl (sodium kiloraidi)
A ko ni alaye siwaju sii nipa awọn aati kemikali yii.
Aniline hydrochloride; CI76001; Benzenamine hydrochloride
C6H5NH3Cl + NaOH → C6H5NH2 + H2O + NaCl AgNO3 + C6H5NH3Cl → AgCl + C6H5NH3KO3 C6H5NH3Cl + CH3NH2 . C6H5NH2 + CH3NH3Cl Wo gbogbo awọn idogba pẹlu C6H5NH3Cl bi ifaseyiniṣuu soda hydroxide
NÁOH + C6H5Br → C6H5Lori + H2O + NaBr NÁOH + CH3-CH.2-KOO-CH2-C6H5 . C6H5CH2OH + CH3CH2COONA 2NÁOH + NH4HSO4 H 2H2O + Na2SO4 + NH3 Wo gbogbo awọn idogba pẹlu NaOH bi aṣaniyaniṣuu soda hydroxide
2H2O + 2NaCl → Cl2 + H2 + 2NÁOH 2H2O + 2Nà → H2 + 2NÁOH Ca (OH)2 + NHCO3 CO CaCO3 + H2O + NÁOH Wo gbogbo awọn idogba pẹlu NaOH bi ọjaiṣuu soda hydroxide
2H2O + 2NaCl → Cl2 + H2 + 2NÁOH 2H2O + 2Nà → H2 + 2NÁOH Ca (OH)2 + NHCO3 CO CaCO3 + H2O + NÁOH Wo gbogbo awọn idogba pẹlu NaOH bi ọjaiṣuu soda hydroxide
2H2O + 2NaCl → Cl2 + H2 + 2NÁOH 2H2O + 2Nà → H2 + 2NÁOH Ca (OH)2 + NHCO3 CO CaCO3 + H2O + NÁOH Wo gbogbo awọn idogba pẹlu NaOH bi ọjaAlaye Nkankan Awọn eniyan diẹ ni o mọ
Awọn ipolowo fọọmu owo-wiwọle ṣe iranlọwọ fun wa ṣetọju akoonu pẹlu didara to ga julọ kilode ti a nilo lati fi awọn ipolowo si? : D
Emi ko fẹ ṣe atilẹyin aaye ayelujara (sunmọ) -: (